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| 1. |
A player sitting on the top of a tower of height 40 observes the angle of depression of a balllying on the ground is 60" The distancebetween the foot of the tower and the ball is5040(A)(B)mV3(C) 403 m(D) 503 m |
| Answer» LET C be the POINT where the ball is. C = 60o (alternate angles) In ABC, tan 60o = AB/BC = 20/x x = 20/ = 20 (/3) = 11.53 m | |