1.

A player takes 0.1 s in catching a ball of mass 150 g moving with velocity of 20m/s. the force imparted by the ball on the hands of the player is

Answer»

3N
0.3N
30N
300N

Solution :Force = Rate of CHANGE of momentum
`=(m(v-u))/(t)= (150xx10^(-3)XX(0-20))/(10^(-1))`
`= -20xx150xx10^(-2)= -30N`
This is the force exertedby the hand on the BALL.
`therefore` The ball EXERTS a force of 30 N on the hands of the player.


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