A playground merry-go-round is at rest, pivoted about a frictionless axis. A child of mass `m` runs along a path tangential to the rim with speed `v` and jumps on to the merry-go-round. If `R` is the radius of the merry-go-round and `I` is its moment of inertia, then the angular velocity of the merry-go-round isA. `(mvR)/(mR^(2)+I)`B. `(mvR)/(I)`C. `(mR^(2))/(mvR)`D. `(I)/(mvR)`

A playground merry-go-round is at rest, pivoted about a frictionless a

1.	A playground merry-go-round is at rest, pivoted about a frictionless axis. A child of mass `m` runs along a path tangential to the rim with speed `v` and jumps on to the merry-go-round. If `R` is the radius of the merry-go-round and `I` is its moment of inertia, then the angular velocity of the merry-go-round isA. `(mvR)/(mR^(2)+I)`B. `(mvR)/(I)`C. `(mR^(2))/(mvR)`D. `(I)/(mvR)`
Answer» `mvR=(I+mR^(2))omegaimpliesomega=(mvR)/(I+mR^(2))`

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