A plot of the number of neutrons `(n)` against the number of protons `(p)` of stable nuclei exhibits upward deviation from linearity for atomic number, `Zgt 20.` For an unstable nucleus having `n//p` ratio less than 1, the possible mode `(s)` of decay is `(are)`A. `beta^(-)`-decay (`beta` emission)B. orbital of K-electron captureC. neutron emissionD. `beta^(+)`-decay (positron emission)

A plot of the number of neutrons `(n)` against the number of protons `

1.	A plot of the number of neutrons `(n)` against the number of protons `(p)` of stable nuclei exhibits upward deviation from linearity for atomic number, `Zgt 20.` For an unstable nucleus having `n//p` ratio less than 1, the possible mode `(s)` of decay is `(are)`A. `beta^(-)`-decay (`beta` emission)B. orbital of K-electron captureC. neutron emissionD. `beta^(+)`-decay (positron emission)
Answer» Correct Answer - b,d When N/P ratio is lower than required for stabiltiy such nuclei can increase N/P ratio by adopting any one of the following mode of decay: (i) Positron `(beta^(+))` emission (ii) K-electron capture (iii) Emission of `alpha`-particles `:.` (b) and (d) options are correct.

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