A point charge `+10 mu C` is at distance of 5cm directly above the center of a square of side 10 cm as shown in Fig. What is the magnitude of the electric flux through the square ? (Hint. Think of the square of the square as one face of a cube with edge 10 cm)

A point charge `+10 mu C` is at distance of 5cm directly above the cen

1.	A point charge `+10 mu C` is at distance of 5cm directly above the center of a square of side 10 cm as shown in Fig. What is the magnitude of the electric flux through the square ? (Hint. Think of the square of the square as one face of a cube with edge 10 cm)
Answer» The square can be considered as one face of a cube of edge 10 cm with a centre where charge q is placed. According to Gauss’s theorem for a cube, total electric flux is through all its six faces. `phi_(Total)=(q)/(in_(0))` Hence, electric flux through one face of the cube i.e., through the square, `phi=(phi_(Total))/(6)` `=(1)/(6)(q)/(in_(0))` Where, `in_(0)` = Permittivity of free space `=8.854xx10^(-12)N^(-1)C^(2)m^(-2)` `q=10muC=10xx10^(-6)C` `thereforephi=(1)/(6)xx(10xx10^(-6))/(8.854xx10^(-12))` `=1.88xx10^(5)Nm^(2)C^(-1)` Therefore, electric flux through the square is `1.88xx10^(5)Nm^(2)C^(-1)`.

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A point charge `+10 mu C` is at distance of 5cm directly above the center of a square of side 10 cm as shown in Fig. What is the magnitude of the electric flux through the square ? (Hint. Think of the square of the square as one face of a cube with edge 10 cm)

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