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InterviewSolution
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A point charge causes an electric flux of `-1.0xx10^(3) N m^(2)//C` to pass through a spherical Gaussian surface of 10.0 cm radius centred on the charge. (a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface ? (b) What is the is the value of the point charge ? |
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Answer» (a) Electric flux, `phi=-1.0xx10^(3)Nm^(2)//C` Radius of the Gaussian surface, r= 10.0 cm Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., `-10^(3)Nm^(2)//C`. (b) Electric flux is given by the relation, `phi=(q)/(in_(0))` Where, q = Net charge enclosed by the spherical surface `in_(0)` = Permittivity of free space = `8.854xx10^(-12)N^(-1)C^(2)m^(-2)` `thereforeq=phiin_(0)` `=-1.0xx10^(3)xx8.854xx10^(-12)` `=-8.854xx10^(9)C` `=-8.854nC` ltBrgt Therefore, the value of the point charge is −8.854 nC. |
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