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A point charge is moving with a constant velocity perpendicular to a uniform magnetic field as shown in the figure. What should be the magnitude and direction of the electric field so that the particle moves undeviated along the same path? |
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Answer» For particle to move undeviated, q vector E + q vector v x vector B = 0 => vector E = - vector v x vector B Given vector v = -v i cap, vector B = -Bk cap ∴ vector E = - (-vi cap) x (- Bk cap) = -vB(-j cap) = vBj cap i.e., magnitude of electric field is vB and its direction is along positive Y-axis. |
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