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A point charge `mu` is placed at origin. Let `vecE_(A), vec E_(B), and vecE_(C)` be the electirc field at three points A (1,2,3), B (1,1,1), and C(2,2,2) due to charge `mu`. ThenA. `vecE_(A)_|_vecE_(B)`B. `vecE_(A)||vecE_(B)`C. `|vecE_(B)| = 4|vecE_(C)|`D. `vecE_(B) = 16 | vecE_(C)|` |
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Answer» Correct Answer - A::C a.,c. `vecE_(A)` is along `OA` and `OA=hati+2hatj+3hatK` `vecE_(B)` is along `OB=hati+hatj-hatK` Since `oAxxOB=(hati+2hatj+3hatK)xx(hati+hatj-hatk)=0` So `OAbotOBrArrvecE_(A)botvecE_(0)` So, option (a) is correct. Since `E_(B)=(kq)/([OB]^(2))=(kq)/(3)` `E_(C)=(kq)/([OC]^(2))=(kq)/(12)` So `(E_(B))/(E_(C))=4` or `|vecE_(B)|=4|vecE_(C)|` So, option (c) is correct. Option (b) and (d) are wrong from the explanation. |
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