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A point charge `q_1=9.1muC` is held fixe at origin. A second pont charge `q_2=-0.42muC` and `a` mass `3.2xx10^-4kg` is placed on the x-axis, `0.96m` from the origin. The second point charge is released at rest. What is its speed when it is `0.24m` from the origin? |
Answer» Correct Answer - B From conservation of mechanical energy, we have Decrease in electrostatic potential =Increase in kinetic energy or `1/2 mv^2=U_i-U_f=(q_1q_2)/(4piepsilon)(1/r_i-1/r_f)` `=(q_1q_2)/(4piepsilon_0)((r_f-r_i)/(r_ir_f))` `:. V=sqrt((q_1q_2)/(2piepsilon_0m)((r_f-r_i)/(r_ir_f)))` `=sqrt(((9.1xx10^-6)(-0.42xx10^-6)xx2xx9xx10^9)/(3.2xx10^-4)((0.24-0.96)/((0.24)(0.96))))` `=26m//s` |
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