InterviewSolution
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InterviewSolution
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A point charge q is placed at a distance d from the centre of a circular disc of radius R. Find electric flux flowing through the disc due to that charge |
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Answer» Solution :We know that total flux originated from a point CHARGE Q in all directions is `(q)/(in_(0))`. This flux is originated in a solid ANGLE `4pi`. In the given case solid angle subtended by the cone subtended by the disc at the point charge is `Omega = 2PI (1- cos theta)` So, the flux of q which is passing through the surface of the disc is `phi = (q)/(in_(0)) (Omega)/(4pi) = (q)/(2in_(0))(1- cos theta)` From the FIGURE, `cos theta = (d)/(sqrt(d^(2) + R^(2)))`, so `phi = (q)/(2 in_(0)) {1-(d)/(sqrt(d^(2) + R^(2)))}` |
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