A point mass 10 g moves in the xy plane with a velocity 2 ms^(-1)along a straight line. Find the magnitude and direction of its angular momentum (i) with respect to the origin O and (ii)with respect to the origin O. The magnitude of the position vector vecris 0.5 m and the angle theta = 30^(@).

A point mass 10 g moves in the xy plane with a velocity 2 ms^(-1)along

1.	A point mass 10 g moves in the xy plane with a velocity 2 ms^(-1)along a straight line. Find the magnitude and direction of its angular momentum (i) with respect to the origin O and (ii)with respect to the origin O. The magnitude of the position vector vecris 0.5 m and the angle theta = 30^(@).
Answer» Solution :`m = 10g = 0.010 kg` `v= 2ms^(-1) ,R = -0.5 m` OO. =` r SIN theta` `=0.5 sin 30` =0.25 m Angular momentum about O `=MVR sin theta` `=0.01 XX 2 xx 0.25` `=5 xx 10^(-3) J.s.` Angular momentum about O. = 0, because the direction of the velocity passes through O..