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A point mass oscillates along the x-axis according to the law `x=x_(0) cos(moegat-pi//4). If the acceleration of the particle is written as `a=A cos(omegat+delta), the . |
Answer» Velocity `v = (dx)/(dt) =- x_(0) omega sin (omegat -(pi)/(4))` Acceleration `a = (dv)/(dt) =- x_(0) omega^(2) cos (omegat -(pi)/(4))` `a = x_(0) omega^(2) cos(omegat+(3pi)/(4)) ….(1)` Given that `a = A cos (omegat +delta) ….(2)` from (1) & (2), `A = x_(0) omega^(2), delta = (3pi)/(4)` |
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