1.

A point mass oscillates along the x-axis according to the law `x=x_(0) cos(moegat-pi//4). If the acceleration of the particle is written as `a=A cos(omegat+delta), the .

Answer» Velocity `v = (dx)/(dt) =- x_(0) omega sin (omegat -(pi)/(4))`
Acceleration `a = (dv)/(dt) =- x_(0) omega^(2) cos (omegat -(pi)/(4))`
`a = x_(0) omega^(2) cos(omegat+(3pi)/(4)) ….(1)`
Given that `a = A cos (omegat +delta) ….(2)`
from (1) & (2), `A = x_(0) omega^(2), delta = (3pi)/(4)`


Discussion

No Comment Found

Related InterviewSolutions