A point mass x = 20 kg, is suspended by a massless spring of constant 2000 N/m. The point mass is released when elongation in the spring is 15 cm. The equation of displacement of particle as function of time is (take, g =10m//s^(2))

A point mass x = 20 kg, is suspended by a massless spring of constant

1.	A point mass x = 20 kg, is suspended by a massless spring of constant 2000 N/m. The point mass is released when elongation in the spring is 15 cm. The equation of displacement of particle as function of time is (take, g =10m//s^(2))
Answer» y = 10 sin 10T Y = 10 cos 10t `y=10 sin(10t+(PI)/(6))` NONE of these Answer :C