A point moves in the xy-plane such that the sum of its distances from the two mutually perpendicular lines is always equal to 5 units. The area (in square units) enclosed by the locus of the point is

A point moves in the xy-plane such that the sum of its distances from

1.	A point moves in the xy-plane such that the sum of its distances from the two mutually perpendicular lines is always equal to 5 units. The area (in square units) enclosed by the locus of the point is
Answer» Here, the point moves in the xy-plane such that the sum of its distances from the two mutually perpendicular lines is always equal to 5 units. `:. \|x\|+\|y\| = 5` `=>x+y = 5, x-y = 5, -x+y = 5, -x-y = 5` If we draw these lines on coordinate axis, it will a square of side `5sqrt2(sqrt(5^2+5^2))` units. Please refer to video to see the square in the diagram. `:.` Area enclosed = Area of square `= (5sqrt2)^2 = 50` square units

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A point moves in the xy-plane such that the sum of its distances from the two mutually perpendicular lines is always equal to 5 units. The area (in square units) enclosed by the locus of the point is

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