A point moves rectilinearly with deceleration which depends on the velocity v of the particle as a=k√v, where k is a positive constant. At the initial moment the velocity of the point is equal to v0. What distance will it cover before it stops ?

A point moves rectilinearly with deceleration which depends on the vel

1.	A point moves rectilinearly with deceleration which depends on the velocity v of the particle as a=k√v, where k is a positive constant. At the initial moment the velocity of the point is equal to v0. What distance will it cover before it stops ?
Answer» A point moves rectilinearly with deceleration which depends on the velocity $v$ of the particle as $a = k \sqrt{v}$ , where $k$ is a positive constant. At the initial moment the velocity of the point is equal to $v_{0}$ . What distance will it cover before it stops ?

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A point moves rectilinearly with deceleration which depends on the velocity v of the particle as a=k√v, where k is a positive constant. At the initial moment the velocity of the point is equal to v0. What distance will it cover before it stops ?

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