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A point moves such that its displacement as a function of time is given by `x^3 = t^3 + 1`. Its acceleration as a function of time t will beA. `(2)/(x^(5))`B. `(2t)/(x^(5))`C. `(2t)/(x^(4))`D. `(2t^(2))/(x^(5))` |
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Answer» `x^(2)=t^(3)+1 rArr 3x^(2)(dx)/(dt)=3t^(2)` `x^(2)v=t^(2) rArr 2x(dx)/(dt)v+x^(2)a=2t` `2x(t^(4))/(x^(4))+x^(2)a=2trArr x^(2)a=2t-(2t^(4))/(x^(3))` `a=(2t[x^(3)-t^(3)])/(x^(5))rArr a-(2t)/(x^(5))` |
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