InterviewSolution
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InterviewSolution
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A point moves with uniform acceleration and `v_(1), v_(2)`, and `v_(3)` denote the average velocities in the three successive intervals of time `t_(1).t_(2)`, and `t_(3)` Which of the following Relations is correct?.A. `(upsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(3))=(t_(1)-t_(2)):(t_(2)+t_(3))`B. `(upsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(3))=(t_(1)+t_(2)):(t_(2)+t_(3))`C. `(ipsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(3))=(t_(1)-t_(2)):(t_(1)-t_(3))`D. `(upsilon_(1)-upsilon_(2)):(upsilon_(2)-upsilon_(2)-upsilon_(3))=(t_(1)-t_(2)):(t_(2)-t_(3))` |
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Answer» Correct Answer - B Average velocity in uniformly accelerated motion is given by, `upsilon_(av)=(s)/(t)=(ut+(1)/(2)at^(2))/(t)=u+(1)/(2)at` Now, `upsilon_(1)=u+(1)/(2)at_(1), upsilon_(2)=(u+at_(1))+(1)/(2)at_(2)` and `upsilon_(3)=u+a(t_(1)+t_(2))+(1)/(2)at_(3)` `therefore upsilon_(1)-upsilon_(2): upsilon_(2)-upsilon_(3)=(t_(1)+t_(2)):(t_(2)+t_(3))` |
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