InterviewSolution
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A point object is placed on the principal axis of a concave mirror of focal length 20 cm. At this instant object is given a velocity v towards the axis (event-I) or perpendicular to axis (event-2). Then, speed of image A. In event-1 is 2vB. In event-1 is 4vC. In event-2 is 2vD. In event-2 is 4v |
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Answer» Correct Answer - A::B::C `1/v+1/(-30)=(1/(-20)` Solving we get, `v= -60 cm` `m=(v)/(u)=-((-60))/((-30))=-2` Speed of image (in event-1) is `m^(2)` times and m times in event-2. |
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