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A point P lies on the axis of a ring of mass M and radius a, at a distance a from its centre C. A small particle starts from P and reaches C under gravitational attraction only. Its speed at C will be(a) √(2GM/a)(b) √(2GM/a (1 - 1/√2))(c) (2GM/a (√2 - 1)) (d) zero |
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Answer» Correct Answer is: (b) √(2GM/a (1 - 1/√2)) VP = - GM / (√r2 + a2), VC = - GM/a, 1/2 mv2 = m [VP - VC]. |
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