A point P on the line 3x + 5y – 15 = 0 is equidistant from the coord

1.	A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. P can lie in (A) first quadrant(B) first or second quadrant(C) first or third quadrant(D) any quadrant
Answer» Correct option (B) first or second quadrant Explanation : The point (x, y) is equidistant from both axes \|x\| = \|y\| ⇒ y = ±x. 1. y = x and (x, y) lies on the line 3x + 5y ⇒ x = 15/8 y = 15/8 ⇒ P lies in the first quadrant. 2. y = -x and (x, y) lies on 3x + 5y = 15 ⇒ x = 15/2, y = 15/2 ⇒P lies in the second quadrant.

A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. P can lie in (A) first quadrant(B) first or second quadrant(C) first or third quadrant(D) any quadrant

Answer»

Correct option (B) first or second quadrant

Explanation :

The point (x, y) is equidistant from both axes

|x| = |y| ⇒ y = ±x.

1. y = x and (x, y) lies on the line 3x + 5y ⇒ x = 15/8

y = 15/8 ⇒ P lies in the first quadrant.

2. y = -x and (x, y) lies on 3x + 5y = 15 ⇒ x = 15/2, y = 15/2 ⇒P lies in the second quadrant.

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A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. P can lie in (A) first quadrant(B) first or second quadrant(C) first or third quadrant(D) any quadrant

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