A point performs simple harmonic oscillation of period T and the equation of motion is given by x=a sin(ωt+π6). After the elapse of what fraction of the time peirod, the velocity of the point will be equal to half of its maximum velocity?

A point performs simple harmonic oscillation of period T and the equat

1.	A point performs simple harmonic oscillation of period T and the equation of motion is given by x=a sin(ωt+π6). After the elapse of what fraction of the time peirod, the velocity of the point will be equal to half of its maximum velocity?
Answer» A point performs simple harmonic oscillation of period $T$ and the equation of motion is given by $x = a s i n (ω t + \frac{π}{6}) .$ After the elapse of what fraction of the time peirod, the velocity of the point will be equal to half of its maximum velocity?

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A point performs simple harmonic oscillation of period T and the equation of motion is given by x=a sin(ωt+π6). After the elapse of what fraction of the time peirod, the velocity of the point will be equal to half of its maximum velocity?

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