A pond has a layer of ice of thickness 0.25 m on its surface the temperature of the atmosphere is 10^(@) C.Find out the time required to increase the thickness of the layer of ice 0.5 "mm". K of ice = 2 "Wm"^(-2) "K"^(-1). Density of ice = 900 "kg m"^(-3) latent heat of fusion of ice = 336 "KJ kg"^(-1).

A pond has a layer of ice of thickness 0.25 m on its surface the tempe

1.	A pond has a layer of ice of thickness 0.25 m on its surface the temperature of the atmosphere is 10^(@) C.Find out the time required to increase the thickness of the layer of ice 0.5 "mm". K of ice = 2 "Wm"^(-2) "K"^(-1). Density of ice = 900 "kg m"^(-3) latent heat of fusion of ice = 336 "KJ kg"^(-1).
Answer» Solution :`X = 0.2502 m, Q = mL = 0.45 A XX 336 xx 10^(3)J, t = Qx// KA (theta_1 - theta_2) = 1891` second