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A pond of depth 20 cm is filled with water of refractive index `4//3`. Calculate apparent depth of the tank when viewed normally. |
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Answer» Here, real depth of pond, `x = 20 cm`, refractive index of water, `.^(a)n_(w) = 4/3` apparent depth, `y = ?` As `.^(a)n_(w) = x/y`, `y = x/(.^(a)n_(w)) = 20/(4//3) = 20xx(3)/(4) = 15 cm` |
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