1.

A position of particle is `x=`at`+bt^(2)-ct^(3)` find out velocity when acceleration is zero (1) `v=a+b^2/(3c)` (2) `v=a-b^2/(3c)` (3) `v=2a-b^2/(3c)` (4) None of theseA. `v-a+(b^(2))/(3c)`B. `v-a-(b^(2))/(3c)`C. None of theseD. 1

Answer» Correct Answer - A


Discussion

No Comment Found

Related InterviewSolutions