1.

A positive charge q is placed in front of conducting solid cube at a distance d from its centre. Find the electric field at the centre of the cube due to the charges appearing on its surface.

Answer» Correct Answer - ` q/ (4 pi varepsilon_0d^2)` towards the charge (q)
`vec E_q + vec E_("induced") =0 rArr vec E_("induced") =- vec e_q`
`vec E_("induced") = q/(4 pi in_0 d^2)` tiwards charge `q`.


Discussion

No Comment Found

Related InterviewSolutions