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A positive integer, when divided by 88, gives the remainder 61. What will be the remainder when the same number is divided by 11? |
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Answer» Let the positive integer be “x” x = 88 x y + 61(a = pq + r) Since 88 is a multiple of 11 61 = 11 x 5 + 6 ∴ The remainder is 6 |
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