1.

A positive integer, when divided by 88, gives the remainder 61. What will be the remainder when the same number is divided by 11?

Answer»

Let the positive integer be “x” 

x = 88 x y + 61(a = pq + r)

Since 88 is a multiple of 11

61 = 11 x 5 + 6

∴ The remainder is 6



Discussion

No Comment Found