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A positively charged particle P enters the region between two parallel plates with a velocity u, in a direction parallel to the plates. There is a uniform electric field in this region. P emerges from this region with a velocity v. Taking C as a constant, v will depend on u as A. `v = Cu`B. `v = (sqrt(u^2+Cu))`C. `v = (sqrt(u^2+C/u))`D. `v = (sqrt(u^2 + C/u^2))` |
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Answer» Correct Answer - D `l` is the length of the each tube `u_(x)=u` constant. Time of travel between the plates is `t=l//u` let `a` be constant acceleration in y-direction so `v_(y)=at` when the particle emerges from the plates so `v^(2)=u_(x)^(2)+v_(y)^(2)=u^(2)+a^(2)t^(2)` `=u^(2)+a^(2)(l^(2))/(u^(2))=u^(2)+(C)/(u^(2))` (where `a^(2)l^(2)=C`) So, `v=sqrt(u^(2)+(C)/(u^(2)))` |
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