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A positron is emitted from `._(11)Na^(23)` . The ratio of the atomic mass and atomic number of the resulting nuclide isA. 22/10B. 22/11C. 23/10D. 23/12 |
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Answer» Correct Answer - c `._(1)^(1) H to ._(0)^(1)n + underset("Positron")(._(+1)^(0)e)` |
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