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A possible equation of L is (A) x 3y 1 (B) x 3y 1 (C) x 3y 1 (D) x 3y 5A. `x-sqrt(3) y =1`B. `x+ sqrt(3) y =1`C. `x-sqrt(3) y = -1`D. `x+sqrt(3) y =5` |
Answer» Correct Answer - 1 The equation of tangent at `P(sqrt(3),1)` is `sqrt(3)x+y=4` The slope of line perpendicular to the above tangent is `1//sqrt(3)`. So, the equations of tangents with slope `1//sqrt(3)` to `(x-3)^(2)+y^(2)=1` will be `y= (1)/(sqrt(3))(x-3)=- 1sqrt(1+(1)/(3))` or `sqrt(3) y = x-3+- (2)` i.e., `sqrt(3) y = x-1 ` or `sqrt(3) y = x-5` |
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