A pot has two taps. The first tap can fill it in 4 hours and the secon

1.	A pot has two taps. The first tap can fill it in 4 hours and the second tap can empty it in 16 hours. If both the taps are opened together, then what will be the time taken by pot to fill?1. \(5\frac{1}{2}\) hours2. 10 hours3. 6 hours4. \(5\frac{1}{3}\) hours
Answer» Correct Answer - Option 4 : \(5\frac{1}{3}\) hours Given: The first tap can fill it in 4 hours and the second tap can empty it in 16 hours Concept: If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank. Calculation: Part of the pot filled by both the taps in 1 hours = \(\frac{1}{4} - \frac{1}{{16}}\) ⇒ \(\frac{{4 - 1}}{{16}}{\rm{}} = {\rm{}}\frac{3}{{16}}\) Time = (16/3) hours = \(5\frac{1}{3}\) hours ∴ The required time is \(5\frac{1}{3}\) hours.

A pot has two taps. The first tap can fill it in 4 hours and the second tap can empty it in 16 hours. If both the taps are opened together, then what will be the time taken by pot to fill?1. \(5\frac{1}{2}\) hours2. 10 hours3. 6 hours4. \(5\frac{1}{3}\) hours

Answer» Correct Answer - Option 4 : \(5\frac{1}{3}\) hours

Given:

The first tap can fill it in 4 hours and the second tap can empty it in 16 hours

Concept:

If a tap can fill a tank in x hours, then the tank filled by the tap in 1 hour = 1/x of the total tank.

Calculation:

Part of the pot filled by both the taps in 1 hours = \(\frac{1}{4} - \frac{1}{{16}}\)

⇒ \(\frac{{4 - 1}}{{16}}{\rm{}} = {\rm{}}\frac{3}{{16}}\)

Time = (16/3) hours = \(5\frac{1}{3}\) hours

∴ The required time is \(5\frac{1}{3}\) hours.

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