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A potential of 10000 V is applied across an x-ray tube. Find the ratio of de-Broglie wavelength associated with incident electrons to the minimum wavelength associated with x-rays. |
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Answer» Debroglie wave length of incident electron is `lambda_(1)=h/sqrt(2meV)`...1 Shortest wavelength of `x`ray photon is `lambda_(2)=(he)/(Ve)`...(2) `rArr lambda_(1)/lambda_(2)=1/csqrt((V/2)(e/m))=0.1` |
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