A potentiometer wire gives a null point at 3 m for a wire of length 3.5 m. The primary circuit contains only a battery of emf 10 V. The emf of secondary cell is 8 V. What is the internal resistance of the battery in the primary circuit (in ohms) if the resistance of the potentiometer wire is 14 Ω?

A potentiometer wire gives a null point at 3 m for a wire of length 3.

1.	A potentiometer wire gives a null point at 3 m for a wire of length 3.5 m. The primary circuit contains only a battery of emf 10 V. The emf of secondary cell is 8 V. What is the internal resistance of the battery in the primary circuit (in ohms) if the resistance of the potentiometer wire is 14 Ω?
Answer» A potentiometer wire gives a null point at $3 m$ for a wire of length $3.5 m$ . The primary circuit contains only a battery of emf $10 V$ . The emf of secondary cell is $8 V$ . What is the internal resistance of the battery in the primary circuit (in ohms) if the resistance of the potentiometer wire is $14 Ω$ ?

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A potentiometer wire gives a null point at 3 m for a wire of length 3.5 m. The primary circuit contains only a battery of emf 10 V. The emf of secondary cell is 8 V. What is the internal resistance of the battery in the primary circuit (in ohms) if the resistance of the potentiometer wire is 14 Ω?

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