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A potentiometer wire is `100 cm` long hand a constant potential difference is maintained across it. Two cells are connected in series first to support one another and then in opposite direction. The balance points are obatined at `50 cm` and `10 cm` from the positive end of the wire in the two cases. The ratio of emfs is:A. `3 : 2`B. `5 : 1`C. `5 : 4`D. `3 : 4` |
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Answer» Correct Answer - A (a) `(E_(1) + E_(2))/(E_(1) + E_(2)) = (50)/(10)` `implies (2E_(1))/(2E_(2)) = (50 + 10)/(50 - 10) implies (E_(1))/(E_(2)) = (3)/(2)` |
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