A potentiometer wire is 5 m long and a potential difference of 6V is maintained between its ends. Find the emf of a cell which balance against a length of 180 cm of the potentiometer wire.

A potentiometer wire is 5 m long and a potential difference of 6V is m

1.	A potentiometer wire is 5 m long and a potential difference of 6V is maintained between its ends. Find the emf of a cell which balance against a length of 180 cm of the potentiometer wire.
Answer» Length of potentiometer wire L = 5 m Potentiall difference V = 6 volt Potential gradient `phi = (V)/(L) = (6)/(5) = 1.2 V //m` Balancing length l = 180 cm = 1.80 cm Emf of the cell `E = phi l` `= 1.2 xx 1.8 = 2.16 V`.

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A potentiometer wire is 5 m long and a potential difference of 6V is maintained between its ends. Find the emf of a cell which balance against a length of 180 cm of the potentiometer wire.

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