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A potentiometer wire is 5m long and a potential difference of 6 V is maintained between its ends. Find the emf of a cell which balances against a length of 180 cm of the potentiometer wire. |
Answer» Length of potentiometer wire L = 5m Potential difference V = 6 Volt Potential gradient ϕ = V/L = 6/5 = 1.2V/M Balancing length l = 180cm = 1.80m Emf of the cell E = ϕl = 1.2 × 1.8 = 2.16V |
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