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A pressure exerted by mercury at the bottom of a container of area of cross section 2 cm^(2) is 10 Pa. Determine the weight of the mercury in the container. |
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Answer» <P> SOLUTION :PRESSURE `P=("Thrust(weight)")/("Area")`Thrust =Area `xx` pressure `=2xx10-4xx10=2xx10^(-3)N` Weight of mercury `=2xx10^(-3) N`. |
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