1.

A pressure exerted by mercury at the bottom of a container of area of cross section 2 cm^(2) is 10 Pa. Determine the weight of the mercury in the container.

Answer»

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SOLUTION :PRESSURE `P=("Thrust(weight)")/("Area")`
Thrust =Area `xx` pressure `=2xx10-4xx10=2xx10^(-3)N`
Weight of mercury `=2xx10^(-3) N`.


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