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A prism has refractive index `sqrt((3)/(2))` and refractive angle `90^@`. Find the minimum deviation produced by prismA. `40^(@)`B. `45^(@)`C. `30^(@)`D. `49^(@)`

Answer» Correct Answer - C
`mu=(sin (delta_(m)+A)//2)/(sinA//2)`
`sqrt(3)/(2)=mu=(sin (delta_(m)+A)//2)/(sin45^(@))`
`sqrt(3)/(2)xx(1)/(sqrt(2))=sin(delta_m+A)//2 rArr(sqrt(3))/(2)=sin(delta_(m)+A)//2`
`sin60^(@)=sin(delta_m+A)//2 rArr delta_(m)+A=120^(@)`
`delta_(m) = 30^(@)`


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