A projectile has a range of 50 m and reaches a maximum height of 10m . Calculate the angle at which the projectile is fired .

A projectile has a range of 50 m and reaches a maximum height of 10m .

1.	A projectile has a range of 50 m and reaches a maximum height of 10m . Calculate the angle at which the projectile is fired .
Answer» Solution :Here R = 50 m, H = 10M , `theta` = ? ` R = (u^(2) sin 2 theta)/(g)` `= (2u^(2) sin theta cos theta)/(g) "" . . . (1)` MAXIMUM height, `H = (u^(2) sin^(2) theta)/( 2G) "". . . (2)` Dividing (2) by (1) , we get `(H)/(R) = (u^(2) sin^(2) theta)/( 2g) XX (g) / (2 u^(2) sin theta cos theta)` `= (1)/(4) tan theta` (or)`tan theta = (4H)/(R) = (4 xx 10)/(50) = 0 . 8` (or) `theta = tan^(-1) (0.8) = 38 . 66^(@)`