A projectile has the maximum range of 500m. If the projectile is now thrown on an inclined plane of 30^(0) with the same speed, what is the distance covered by it along the inclined plane?

A projectile has the maximum range of 500m. If the projectile is now t

1.	A projectile has the maximum range of 500m. If the projectile is now thrown on an inclined plane of 30^(0) with the same speed, what is the distance covered by it along the inclined plane?
Answer» Solution :`R_(max)=(u^(2))/(G)"":.500=(u^(2))/(g)orusqrt(500g)` `V^(2)-u^(2)=2gs rArr 0-500g =2xx-(gsin30^(0))XXX` x=500m.