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A projectile has the same range `R` for two angles of projections but same speed. If `T_(1)` and `T_(2)` be the times of flight in the two cases, then Here `theta` is the angle of projection corresponding to `T_(1)`.A. `T_(1)T_(2) prop R`B. `T_(1)T_(2)propR^(2)`C. `(T_(1))/(T_(2))=tantheta`D. `(T_(1))/(T_(2))=cot theta`

Answer» Correct Answer - A::C


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