1.

A projectile is any body that is given an initial velocity and then follows a path determined entriely by the effects of gruaitional acceleration and air resistance.Derive an expression for time to reach maximum height and hence the time off light of a projectille,

Answer»

Solution :TIME TAKER! to reach the maximum HEIGHT `v_y=u_y+a_utalpha=usintheta-"GT"t=(usintheta)/g` SINCE time of ascend is equal to time of descend ,`T=2t=(2usintheta)/g`


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