InterviewSolution
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InterviewSolution
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a projectile is fired from the surface of the earth with a velocity of `5ms^(-1)` and angle `theta` with the horizontal. Another projectile fired from another planet with a velocity of `3ms^(-1)` at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth.The value of the acceleration due to gravity on the planet is in `ms^(-2)` is given `(g=9.8 ms^(-2))`A. `5.9`B. `16.3`C. `110.8`D. `3.5` |
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Answer» Correct Answer - D `R = (u_(1)^(2))/(g_(1)) sin 2theta = (u_(2)^(2))/(g_(2))sin 2theta` `g_(2) = ((u_(2))/(u_(1)))^(2) g_(1) = ((3)/(5))^(2) xx 9.8 = 3.5 m//s^(2)` |
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