A projectile is fired horizontally with a velocityu . Obtain the expression for speed of theparticle when it hits theground .

A projectile is fired horizontally with a velocityu . Obtain the expre

1.	A projectile is fired horizontally with a velocityu . Obtain the expression for speed of theparticle when it hits theground .
Answer» Solution :When the projectile hits the GROUND after INITIALLY thrown HORIZONTALLY from the top of tower of height h . The time of flight is given by `t = sqrt((2h)/(g))` the horizontal component velocity of the projectile remains the same i.e.,` v_(x) = u` Hence the vertical component velocity of the projectile at time T is given by ` v_(y) = gT = g sqrt((2h)/(g)) = sqrt(2gh)` The speed of the particle when it reaches the ground is `V = sqrt (u^(2) + 2 g h)`.