A projectile is fired with Kinetic energy 1 KJ. If the range is maximu

1.	A projectile is fired with Kinetic energy 1 KJ. If the range is maximum, what is its Kinetic energy, at the highest point?
Answer» Here \(\frac{1}{2}\) mv =1kJ=1000 J, θ = 45° At the highest point, K.E. = \(\frac{1}{2}\) m (v cos0)² = \(\frac{1}{2}\) \(\frac{mv^2}{2}\) = \(\frac{1000}{2}\) = 500 J.

A projectile is fired with Kinetic energy 1 KJ. If the range is maximum, what is its Kinetic energy, at the highest point?

Answer»

Here \(\frac{1}{2}\) mv =1kJ=1000 J, θ = 45°

At the highest point, K.E. = \(\frac{1}{2}\) m (v cos0)² = \(\frac{1}{2}\) \(\frac{mv^2}{2}\) = \(\frac{1000}{2}\) = 500 J.

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A projectile is fired with Kinetic energy 1 KJ. If the range is maximum, what is its Kinetic energy, at the highest point?

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