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A projectile is fired with kinetic energy 1kJ. If the range is maximum, what is its kinetic energy, at the highest point ? |
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Answer» Solution :Here `(1)/(2)mv^(2)=1kJ=1000J,theta=45^(@)` At the highest POINT K.E. `=(1)/(2)m(vcostheta)^(2)=(1)/(2)(mv^(2))/(2)=(100)/(2)=500J` |
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