A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :A. `y=2x-5x^(2)`B. `4y=2x-5x^(2)`C. `4y=2x-25x^(2)`D. `y=x-5x^(2)`

A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) )

1.	A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :A. `y=2x-5x^(2)`B. `4y=2x-5x^(2)`C. `4y=2x-25x^(2)`D. `y=x-5x^(2)`
Answer» Correct Answer - A

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A projectile is given an initial velocity of ` ( hat(i) + 2 hat (j) ) m//s`, where ` hat(i)` is along the ground and `hat (j)` is along the vertical . If ` g = 10 m//s^(2) `, the equation of its trajectory is :A. `y=2x-5x^(2)`B. `4y=2x-5x^(2)`C. `4y=2x-25x^(2)`D. `y=x-5x^(2)`

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