1.

A projectile is projected with a velocityv_(0) at an angletheta with the horizontal as shown in figure. The angular momentum of particle about the origin:

Answer»

is zero when particle is at the origin
is `(-mv^(3) sin^(2) THETA cos theta)/(2g) hatk` when particle is at the HIGHEST point of trajectory
is `(-2mv^(2) sin^(2) theta cos theta)/g hatk` when particle is just about to hit ground
downward FORCE of GRAVITY exerts a torque in `-z` direction.

Answer :A::B::C::D


Discussion

No Comment Found