1.

A projectile is projected with the initial velocity `(6i + 8j) m//s`. The horizontal range is `(g = 10 m//s^(2))`A. `96 m`B. `960 m`C. `9.6 m`D. `4.8 m`

Answer» Correct Answer - C
`vec(u) = 6 hat(i) + 8 hat(j) = u cos theta hat(i) + u sin theta hat(j)`
`R = (u^(2))/(g)sin 2 theta = (2)/(g) (u cos theta)(u sin theta)`
`= (2)/(10)(6)(8) = 9.6 m`


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