

InterviewSolution
Saved Bookmarks
1. |
A projectile is thrown at angle `beta` with vertical.It reaches a maximum height `H`.The time taken to reach the hightest point of its path isA. `sqrt(H/g)`B. `sqrt((2H)/g)`C. `sqrt(H/(2g))`D. `sqrt((2H)/(g cos theta))` |
Answer» Correct Answer - B `t=sqrt((2H)/g)` |
|