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A projectile is thrown in the upward direction making an angle of 60^(@) with the horizontal direction with a velocity of 147 ms^(-1). Then the time after which its inclination with the horizontal is 45^(@), is: |
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Answer» 15s `v cos 45^(@)=u cos 60^(@) =u=147m//s` Now, `v SIN 45^(@)=u sin 60^(@)-gt` |
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